[LeetCode] Reorder Data in Log Files - 문자열 - 파이썬

April 02, 2021

Description

You are given an array of logs. Each log is a space-delimited string of words, where the first word is the identifier.

There are two types of logs:

Letter-logs: All words (except the identifier) consist of lowercase English letters. Digit-logs: All words (except the identifier) consist of digits. Reorder these logs so that:

The letter-logs come before all digit-logs. The letter-logs are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers. The digit-logs maintain their relative ordering. Return the final order of the logs.

Example 1:

Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
Explanation:
The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".
The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".

Example 2:

Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]

Constraints:

1 <= logs.length <= 100 3 <= logs[i].length <= 100 All the tokens of logs[i] are separated by a single space. logs[i] is guaranteed to have an identifier and at least one word after the identifier.

내 코드

class Solution:
    def reorderLogFiles(self, logs: List[str]) -> List[str]:
        num = []
        let = []
        for log in logs:
            if log.split()[1].isdigit() :
                num.append(log)
            else :
                let.append(log)
        let.sort(key = lambda x : (x.split()[1:], x.split()[0]))
        return let+num

뒤에 부분을 체크해서 숫자면 숫자 배열에, 아닐 경우 문자 배열에 넣고, 문자 배열의 경우 내용을 첫 번째 기준으로 정렬하고, 식별자를 두 번째 기준로 해서 정렬한 후에 숫자 배열은 입력 순서니까 그대로 두고 두 배열을 붙여서 리턴했다.